Speed Of Light May Not Be Constant After All, Physicists Say

Apr 29, 2013 | Posted by: roboblogger | Full story: Switched

The speed of light is constant, or so textbooks say. But some scientists are exploring the possibility that this cosmic speed limit changes, a consequence of the nature of the vacuum of space.

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“Geologist [I'm Climate Change]”

Since: Mar 07

Nuneaton

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#1
May 1, 2013
 
Interesting

The speed of light DOES change in the medium it passes through. the result being refraction of the beam.

This may actually be part of the cause of the lensing effects of big galaxy clusters with a pool of hot rarified gas between the giant ellipticals.

It may go a mite faster outside of the galactic disc.

It may also go rather faster in the voids.

Have a nice day: Ag
SpaceBlues

Houston, TX

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#2
May 1, 2013
 
There are no voids, Adrian.
nakayama

Yokohama, Japan

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#3
May 25, 2013
 
A simple idea occurs. Allow me to post, please.

Imagine circular waves of light that are emitted from a point source. These circular waves (and these wavelength) will not be disturbed with observer's motion.

Then, light speed must be variable (to observers).
nakayama

Nihon'odori, Japan

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#4
May 28, 2013
 
There are two space ships. These are observing a star. One observes red-shift and the other observes blue-shift. How does space (extends outside the space ships) change "physically" ?

If there is no change, it will be impossible to attribute the cause to space.
nakayama

Yokohama, Japan

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#5
May 29, 2013
 
A disk is rotating horizontally. From obliquely above, plane waves of light are coming. How is it explained with theory of constancy of light speed ?
nakayama

Yokohama, Japan

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#6
Jun 7, 2013
 
In a forum, i wrote as follows. "When there is no observer, how about wavelength of coming light (Imagine star light)?"

If invariability of wavelength (with observer's motion) is accepted, relativity will collapse inevitably, i think.
nakayaqma

Yokohama, Japan

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#7
Jun 10, 2013
 
Also, propagators (of relativity) donít refer to radar trap or speed gun at all. Thus, they seem to me to not be fair always.
nakayama

Yokohama, Japan

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#8
Jun 23, 2013
 
Allow me to show a thought experiment (lacks freshness).

In outer space, a laser beam is divided with half mirror (angle formed by two divided beams is 45 degrees). Along two paths of beam, one space ship approaches toward the half mirror and the other recedes from the half mirror (at the same speed). How about wavelength of coming beams ?
nakayama

Yokohama, Japan

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#9
Jun 29, 2013
 
Two disks are rotating (axis is horizontal) and two laser beams are coming from above. One beam is incident on ascending edge of one disk and the other beam is incident on descending edge of the other disk (other precondition are the same). On the edge, if waves are marked, intervals of marks (of two disks) is different. It will mean that light speed relative to edges is different.
nakayama

Nihon'odori, Japan

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#10
Jun 30, 2013
 
Allow me to rewrite a part of previous post ; "On the edge, if waves are marked, intervals of marks" as follows. "When horizontal lines (pass the positions where light waves and a rotating point on the edge meet) are shown, intervals of these parallel lines". Sorry, it's complicated a little.
nakayama

Yokohama, Japan

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#11
Jul 12, 2013
 
Imagine a light path coming from a star. There is a formula "light speed = frequency x wavelength". Which of the three is unchangeable with observer's motion ? Obviously, it's wavelength. Other two are changeable.
nakayama

Nihon'odori, Japan

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#12
Aug 4, 2013
 
In formula ; c=&#955;f, wavelength(&#955;) of coming light is unchangeable (with observerís motion). Reason is that itís a fact of the past.
nakayama

Yokohama, Japan

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#13
Aug 6, 2013
 
About my last post ; In it, "the past" is an expression of "fixed already". But it is unclear. sorry. However, perhaps, wavenumber will be unchangeable digital information. It will be digital letter coming from the past.

Suppose that wavelength is possible to have only fixed sole value. Still, frequency and light speed will change continuously (to a moving observer).
nakayama

Yokohama, Japan

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#14
Aug 8, 2013
 
Before an observer's eyes, a beam of star light is passing (supposed from right to left). On the left, there is a second observer (observes this beam). It's impossible to imagine that to the first observer, wavelength is changeable with the state of a second observer.
nakayama

Yokohama, Japan

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#15
Aug 18, 2013
 
As far as light speed is constant, wavelength is unchangeable. In vacuum, light speed is constant always (so, speed of coming light [relative to an observer] changes).
nakayama

Nihon'odori, Japan

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#16
Aug 23, 2013
 
As mentioned before, light speed relative to an observer changes. Now an observer is replaced with a mirror. It shows that in vacuum, light is propagated in two different ways. With this "conclusion", various difficulties will be solved.
nakayama

Yokohama, Japan

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#17
Aug 25, 2013
 
P.S. In everywhere of the universe, the emission theory will be valid for a few seconds (after emission from the sources ; in vacuum). And then, follows aether frame. All phenomena will be explained with this, i believe. Such as behavior of laser beam observed between moon and earth, the same speed of light of binary stars, result of MMX (done in vacuum), light-time correction, aberration and so on. A thought experiment with a mirror shows above.
nakayama

Yokohama, Japan

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#18
Aug 26, 2013
 
P.S. to Thursday Aug 8's my post

Before the first observer's eyes (at a standstill), imagine two points (distance is 2 meters) on the light path (fixed star's frequency is constant). If light speed is the same, frequency at two points is the same. So, wavelength is the same also. A second observer can't change this wavelength.
nakayama

Yokohama, Japan

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#19
Sep 10, 2013
 
Standing wave of light (formed in the glass ; horizontally) will be unchangeable to a moving observer (moves horizontally ; relative to the glass). So, Fizeau experiment (with flowing water ; 1851) must be reexamined, I think.
nakayama

Tokyo, Japan

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#20
Sep 15, 2013
 
In a glass, standing waves of light appear. And it is projected on to a screen. How are the two visible to a moving observer ?

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