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Since: May 13

Location hidden

#61854 Nov 3, 2013
yehoshooah adam wrote:
<quoted text>

rabbee: oh come on, i gave to you the simplest equation you could not find on Wikipedia. and all you can do is give me a load of bull crap. when the answer is simply 1.414 phase angle 45* polar co-ordanance because the square root of two is 1.414. and as long as the imaginary number and the real number are equal, the phase angle is always 45 degrees.
Retard,

How did you get 1.414 which is (2)^1/2?

for a phase angle of 45,

L45 = Pi/4 = 0.785.

For the real and imaginary number part:

A = x + jy or B = w + jz

So, A + B = x + jy + w + jz =(x + w)= j(y + z)

If you want to convert the polar form into the rectangular form:

These are the equations needed:

Z = x + jy = aLtheta

As for the sinsoidal part:

Vt = VmSin(wt + theta)

Now, you typed this:

what are the vector sum, and polar cordanance of v1 + vj1 = vt

What do you mean by polar cordanance? It should be polar-co-ordinates, not polar cordanance? Understand, retard.

The equations I typed above should be used for the calculations.

Now, using Vt = VmSin(wt + theta), we get for theta = 45 degree:

Vt = VmSin(wt + theta)

Vt = VmSin(wt + 45)volts = Vm/(2)^1/2 x L45 = Vm/1.41 x 0.785 = Vm x 0.556. If Vm is known, we calculate further.

Got it retard?

Give me the detailed calculations of the answer of 1.414 that you arrived at. I want to take a look at the way you arrived at the answer of 1.414 which is wrong. Dunce.

Since: May 13

Location hidden

#61855 Nov 3, 2013
HughBe wrote:
<quoted text>

Greetings my beloved, I am aware that you want to get a FEEL of my monster.
Hi Hugh.

Yes, I want to feel your monstrous fatherly love for me.

I am a bit unwell.

Take care.

Since: May 13

Location hidden

#61856 Nov 3, 2013
HughBe wrote:
<quoted text>

HughBe--- WE all know that you(Frijoles) ONLY believe in and delight in BUNS.

Joel---He takes delight in BOYS' BUMS.

Hugh--- And their BUNS.
Buns?

What're buns?

Since: May 13

Location hidden

#61857 Nov 3, 2013
HughBe wrote:
<quoted text>

I am FULLY aware of what you have said and I have NEVER grouped them with Judahites. They are NORMAL people going about their everyday business seeking to enjoy this life.
Yes.

Since: May 13

Location hidden

#61858 Nov 3, 2013
Rabbee,

Retard,

I want the full working to show how you arrived at an answer of 1.414 which is incorrect. Give the Math involved and then I'll tackle all your mistakes. I am waiting. I have worked out your approach and discovered all the errors.You just make statements without knowing what you're talking about. I will break down the question in small parts and point out all your mistakes.

I am unwell but I will still teach you the Math.

Ok, retard?

LOL.
Voluntarist

United States

#61859 Nov 3, 2013
Frijoles wrote:
How Ayn Rand ruined my childhood
My dad saw objectivism as a logical philosophy to live by, but it tore my family apart
http://www.salon.com/2011/04/05/my_father_the...
spam

“Act Interdimensional ly”

Since: Jan 08

Location hidden

#61861 Nov 3, 2013
Voluntarist wrote:
<quoted text>spam
Not spam, just an article about bad parenting. I have no doubt that many parents take their poorly understood belied system to unpleasant extremes on their children. For example, Joan Crawford, The Branch Davidians and the parents on 'Toddlers and Tiaras'.

That being said, I'm pretty sure a lot more children have had their childhoods irreparably damaged by People magazine than by the collected works of Ayn Rand.
yehoshooah adam

Denver, CO

#61862 Nov 3, 2013
JOEL THUMBS UP wrote:
<quoted text>
Here, this is what I typed:
I said, j^5 =?
So, what difference would it make had I typed it as 1 j^5 =?
In either case the answer is the same.
You got this answer 3.65 which is wrong:
RABBEE TYPED: 1j 5. would be +3.65
Your answer is incorrect.
The correct answer is worked out as follows:
j^5 = 450 degree rotation = 5 pi/2^c = 2.5 pi ^c = 7.85^c
Or, simply put,
j^5 = j^4 x j =((-1)^1/2)^4 x j =+1 x j = j
rabbee: well you did not state a -j in your alleged non-equasion. which would be -0.707 + 2.236 instead of both in the positive field... nor did you state, if they are xl, xc, r, v, i or pi. your equation, lacked both precision and accuracy. leaving the assumption that both parameters as the same. so you don't even know how to write the equation.
yehoshooah adam

Denver, CO

#61863 Nov 3, 2013
JOEL THUMBS UP wrote:
<quoted text>
Retard,
How did you get 1.414 which is (2)^1/2?
for a phase angle of 45,
L45 = Pi/4 = 0.785.
For the real and imaginary number part:
A = x + jy or B = w + jz
So, A + B = x + jy + w + jz =(x + w)= j(y + z)
If you want to convert the polar form into the rectangular form:
These are the equations needed:
Z = x + jy = aLtheta
As for the sinsoidal part:
Vt = VmSin(wt + theta)
Now, you typed this:
what are the vector sum, and polar cordanance of v1 + vj1 = vt
What do you mean by polar cordanance? It should be polar-co-ordinates, not polar cordanance? Understand, retard.
The equations I typed above should be used for the calculations.
Now, using Vt = VmSin(wt + theta), we get for theta = 45 degree:
Vt = VmSin(wt + theta)
Vt = VmSin(wt + 45)volts = Vm/(2)^1/2 x L45 = Vm/1.41 x 0.785 = Vm x 0.556. If Vm is known, we calculate further.
Got it retard?
Give me the detailed calculations of the answer of 1.414 that you arrived at. I want to take a look at the way you arrived at the answer of 1.414 which is wrong. Dunce.
rabbee: the apparent voltage of two out of phase voltages. with an apparent voltage summation of 2, so the actual summation voltage is the square root of 2. as 0.707 + 0.707 = 1.414. and any one with actual experience in electronics would recognize this simple problem, for the half power point of 45 degrees phase angle for two voltages. man you do not even need a slide rule or calculator, for this simple of a two phase problem. which means you lack experience, in electronics. with 45 degrees, always equal to 0.707 of any given value. maybe the simplicity, of the problem fooled you.

you probably don't even know, where most of the power is found in a modulated carrier signal.

how about an even simpler problem, 1i x 1v = x-watts?

Since: May 13

Location hidden

#61864 Nov 3, 2013
yehoshooah adam wrote:
<quoted text>

rabbee: well you did not state a -j in your alleged non-equasion. which would be -0.707 + 2.236 instead of both in the positive field... nor did you state, if they are xl, xc, r, v, i or pi. your equation, lacked both precision and accuracy. leaving the assumption that both parameters as the same. so you don't even know how to write the equation.
Retard,

That was your question, not mine.

I simply asked you j^5 =?

Here, too, you gave the wrong answer.

Next, you asked about this:

V1 + Vj = Vt

and you arbitrarily arrived at an answer of theta = 45 provided real part = imaginary part.

This is wrong.

BTW, did you mean V1 + Vj = Vt? Yes, this is it.

For solving the resultant vector use paralleogram law of vector addition.

For any regular llgm ABDC with AB as base.

Draw DE Ir to base AB such A B E

LDBE = theta, LDAB = alpha

Now,(AD)^2 =(AB + BE)^2 +(DE)^2

=(a +bcostheta)^2 +(bsintheta)^2

So, AD =(a^2 + b^2 + 2abcostheta)^1/2

Tan alpha = DE/AE = bsintheta/a = bcostheta

So, taking components:

horizontal component = V2sinwt

vertical component = V1sin(wt + phi)

.....

Now,

Z = ALtheta (polar form)

Z = x = jy (rect form)

A =(x^2 + y^2)^1/2, theta = tan^-1(y/x)

........

If x = y, theta should work out 45 as the retard said. Let's check:

Z =(x^2 + y^2)^1/2 Ltheta =(2x^2)^1/2 Ltheta = x .(2)^1/2 Ltheta

Ltheta = Z/x.(2)^1/2,

theta = tan^-1(Z/x.(2)^1/2)

..........

Another approach (rect to polar) to get theta = 45, if x = y:

Z = ALtheta

x + jy = ALtheta

x(1 +j)=(x^2 + y^2)^1/2Ltheta

So, Ltheta = x(1 +j)/(x^2 + y^2)^1/2

theta = tan^-1 (x(1 +j)/(x^2 + y^2)^1/2)

So, in both cases there's no sign of theta = 45.

LOL.

Since: May 13

Location hidden

#61865 Nov 3, 2013
yehoshooah adam wrote:
<quoted text>

how about an even simpler problem, 1i x 1v = x-watts?
1i x 1v = 1 amp-volt (watt).

Now, can you mathematically prove that 1 watt = 1 kg-m^2/s^3?

Show all the working steps, retard.
(smiles)

Since: May 13

Location hidden

#61866 Nov 3, 2013
yehoshooah adam wrote:
<quoted text>

rabbee: the apparent voltage of two out of phase voltages. with an apparent voltage summation of 2, so the actual summation voltage is the square root of 2. as 0.707 + 0.707 = 1.414.
Look here, dunce.

How did you arrive at all those arbitrary values?

Show the equations and then I'll calculate.

Your original question was this:

If x = y then theta = 45

which as I have worked out using 2 approaches - polar form and rect to polar form - in a previous post does not show up. So, you're wrong.

Remember,(2)^1/2 converts the maximum amplitude (Am) into an effective or RMS value with the phase angle given in radians, w

For phase value of a sinusoidal wave, you'll have to use this eqn:

At = Am sin(wt + phi)

or in complex form:

Vt = Vm sin(wt + theta)

Example,

Let A = 20, theta = 45

So, Vt = 20 sin(wt + 45)

Vt = 20. L45/(2)^1/2 = 20 x 1/1.41 = 14.18 V

and not what you have said.

This is part of electrical engineering.

Since: May 13

Location hidden

#61867 Nov 3, 2013
I am going out for some time. Later. Bye.
yehoshooah adam

Denver, CO

#61868 Nov 3, 2013
JOEL THUMBS UP wrote:
<quoted text>
Retard,
That was your question, not mine.
I simply asked you j^5 =?
Here, too, you gave the wrong answer.
Next, you asked about this:
V1 + Vj = Vt
and you arbitrarily arrived at an answer of theta = 45 provided real part = imaginary part.
This is wrong.
BTW, did you mean V1 + Vj = Vt? Yes, this is it.
For solving the resultant vector use paralleogram law of vector addition.
For any regular llgm ABDC with AB as base.
Draw DE Ir to base AB such A B E
LDBE = theta, LDAB = alpha
Now,(AD)^2 =(AB + BE)^2 +(DE)^2
=(a +bcostheta)^2 +(bsintheta)^2
So, AD =(a^2 + b^2 + 2abcostheta)^1/2
Tan alpha = DE/AE = bsintheta/a = bcostheta
So, taking components:
horizontal component = V2sinwt
vertical component = V1sin(wt + phi)
.....
Now,
Z = ALtheta (polar form)
Z = x = jy (rect form)
A =(x^2 + y^2)^1/2, theta = tan^-1(y/x)
........
If x = y, theta should work out 45 as the retard said. Let's check:
Z =(x^2 + y^2)^1/2 Ltheta =(2x^2)^1/2 Ltheta = x .(2)^1/2 Ltheta
Ltheta = Z/x.(2)^1/2,
theta = tan^-1(Z/x.(2)^1/2)
..........
Another approach (rect to polar) to get theta = 45, if x = y:
Z = ALtheta
x + jy = ALtheta
x(1 +j)=(x^2 + y^2)^1/2Ltheta
So, Ltheta = x(1 +j)/(x^2 + y^2)^1/2
theta = tan^-1 (x(1 +j)/(x^2 + y^2)^1/2)
So, in both cases there's no sign of theta = 45.
LOL.
rabbee: are you trying to baffle everyone with a line of bs? for the simplest of equations, involving the square root number 1+1. and can't even calculate, what the square root of 2 is. when the phase angle of 45degrees is always going to be the square root of the total of the two numbers.
yehoshooah adam

Denver, CO

#61869 Nov 3, 2013
JOEL THUMBS UP wrote:
<quoted text>
1i x 1v = 1 amp-volt (watt).
Now, can you mathematically prove that 1 watt = 1 kg-m^2/s^3?
Show all the working steps, retard.
(smiles)
rabbee: no i have already entertained you, with too much of your aside constant diversionary vain bs. which is no longer, my area of interest. just to let you know, i do recognize defilade when i see it. camouflage only used, to avoid detection. but is always visible, to the inferadam color-rado spectrum.

Since: May 13

Location hidden

#61870 Nov 3, 2013
How can anyone even consider curing homosexuality when it's clearly not a disease but that it is just a functional mode of sexuality? Besides, what kind of "cure" would be involved? Let's hear from Hugh about the "cure" for homosexuality. LOL.

Since: May 13

Location hidden

#61871 Nov 3, 2013
Hugh,

Can you cure yourself of this so-called disease called homosexuality? Outline the steps of the "cure" involved.

(smiles)
yehoshooah adam

Denver, CO

#61872 Nov 3, 2013
JOEL THUMBS UP wrote:
I am going out for some time. Later. Bye.
rabbee: and don't forget to get, a sheet of graph paper. so you can draw, the vector for +1x ++1y.
yehoshooah adam

Denver, CO

#61873 Nov 3, 2013
in fact draw any two equal numbers, on the +x and +y axis. and tell me if the phase angle, ever deviates from 45degrees.
yehoshooah adam

Denver, CO

#61874 Nov 3, 2013
JOEL THUMBS UP wrote:
How can anyone even consider curing homosexuality when it's clearly not a disease but that it is just a functional mode of sexuality? Besides, what kind of "cure" would be involved? Let's hear from Hugh about the "cure" for homosexuality. LOL.
rabbee: a mental illness, that results from the worship of halooseefer. considered worse than the worship, of hasatan or baal hamolech. so can you tell me what is the cure or prophylaxis is, for this total mental disbelief of G-D here in TheTorah? or what is the cure or prevention for any rebellion, against G-D here in TheTorah? how do you cure russian mental illness, that only considers russians as the only true subtle beast not here in TheTorah? what subtle nation does not vote themselves as, the only true nation not true to G-D here in TheTorah?

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