Messianic Jews say they are persecuted in Israel

Full story: Newsday

Safety pins and screws are still lodged in 15-year-old Ami Ortiz's body three months after he opened a booby-trapped gift basket sent to his family.

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Since: May 13

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#56194
Jul 22, 2013
 
The law is an ass and lawyers are cheats!
Voluntarist

United States

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#56195
Jul 22, 2013
 
Eric wrote:
<quoted text>
What the h-ll was he following the kid for? He called it in and then he started to track him. Kid was protecting himself, if you believe Zimmerman.
You stated that it was an assault by his own admission why are you misrepresenting the facts?

Since: May 13

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#56196
Jul 22, 2013
 
Zimmerman stalked Martin as the latter was running away after being spotted closely surveying people's homes (to burgle, I guess). He turned around and attacked. Police have discovered tools for breaking locks that fell out of Martin's pocket at the spot where he was punching Zimmerman.

Since: May 13

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#56197
Jul 22, 2013
 
Police have discovered tools for breaking locks that fell out of Martin's pocket at the spot where he was punching Zimmerman.

Since: May 13

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#56198
Jul 22, 2013
 
Yawn. Dunces.
Eric

Addison, IL

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#56199
Jul 22, 2013
 
Voluntarist wrote:
<quoted text>
You stated that it was an assault by his own admission why are you misrepresenting the facts?
putting Martin in reasonable fear of a battery by a person who was capable of carrying it out is an assault.
Eric

Addison, IL

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#56200
Jul 22, 2013
 
JOEL THUMBS UP wrote:
Police have discovered tools for breaking locks that fell out of Martin's pocket at the spot where he was punching Zimmerman.
6 days after the incident, police found a jimmy in some bushes. Now how do you believe that a jimmy fell out of Martin's pocket? How do you tie a discover 6 days later to the incident?

“Act Interdimensional ly”

Since: Jan 08

Singapore -- Home of Hot

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#56201
Jul 22, 2013
 
Eric wrote:
<quoted text>
6 days after the incident, police found a jimmy in some bushes. Now how do you believe that a jimmy fell out of Martin's pocket? How do you tie a discover 6 days later to the incident?
Thanks, Nancy Drew! You solved the case!

“Legumes of the World Unite ”

Since: Sep 11

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#56202
Jul 22, 2013
 
Rick Moss wrote:
<quoted text>
Thanks, Nancy Drew! You solved the case!
Hey, speaking of fantasy, how is comic-con?

Since: May 13

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#56204
Jul 22, 2013
 
Most Americans say that the plural of the word formula is formulas when actually it should be formulae. LOL.

Since: May 13

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#56205
Jul 22, 2013
 
HUGH,

Calculate the square root of 95 without using printed tables or a calculator.

You should take less than or around 20 seconds to arrive at the correct answer.

(smiles in advance)

Since: May 13

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#56206
Jul 22, 2013
 
Yawn. Yawn. Yawn. Aha....

Since: May 13

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#56207
Jul 22, 2013
 
METHOD TO DEDUCE THE SQUARE ROOT OF A NUMBER MENTALLY:

HUGH,

Here's how the square root of any number is mentally calculated.

I'll explain the steps in long form.

Take a number, say 95.

How do we find its square root mentally?

Let's see how it is done.

Now, 95 lies between 81 (a perfect square of 9) and 100 (a perfect square of 10).

Remember, 9^2 = 81 and 10^2 = 100.

So, we have:

81......95.......100.

Now, 100 - 81 = 19

19/2 = 9.5

Thus, 81 + 9.5 = 90.5

So, the square root of 90.5 = 9.5 (half-way value between 81 whose square root is 9 and 100 whose square root is 10).

This indicates that the square root of 95 is somewhere above 9.5.

Now, 100 - 90.5 = 9.5

9.5/2 = 4.75

So, 90.5 + 4.75 = 95.25

Hence, 95.25 is the mid-value between 90.5 and 100.

So, square root of 95.25 = 9.75.

Therefore, by slight adjustment, we can say that the square root of 95 would be approximately 9.73 or 9.74 or so.

These calculation steps can be mentally done in 10 to 15 seconds flat.

Enjoy.

(wink wink wink)
Eric

Addison, IL

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#56208
Jul 22, 2013
 
Yawn. Yawn. Yawn.

"or so"? Some scientist you are.

The question was to calculate; not deduce or estimate. Your calculation doesn't meet scientific requirements for precision.

“Legumes of the World Unite ”

Since: Sep 11

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#56209
Jul 22, 2013
 
Cult of Reason wrote:
<quoted text>
Don't hold your breath. You know how MUQ is attracted to hyperbole.
The thing is, I think that in the intellectual environment that MUQ swims in, his missives ARE considered reasoned. I dont think he is used to being challenged, nor do I think he would survive very long out of his subculture.

Since: May 13

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#56210
Jul 22, 2013
 
METHOD TO EXPAND A BINOMIAL WITHOUT USING FORMULA INVOLVING FACTORIALS (!):

Let us expand (a + b)^3

By formula we know that:

(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3 which can further be written as:

a^3 + 3ab (a + b)+ b^3 (taking the HCF).

If we wish to know how this is done we usually resort to Pascal's triangles or to the binomial expansion formula for (a + b)^n which is:

a+b)^n = nC0 a^n.b^0 + nC1 a^(n-1).b^1 + nC2 a^(n-2).b^2 + nC3 a^(n-3).b^3 +......... nCn a^0. b^n.

Remembering that:

nC0 = 1 = nCn,

nC1 = n = nC(n-1)

nC2 = n(n-1)/2!

nC3 = n(n-1)/3! and so on....

Note: nCr = n!/(n-r)! r!= nPr/r!

Oh my! Employing the extended formula of binomial expansion is easy if you're fast with calculations and provided if you have understood the concepts but otherwise it's rather tedious.

So, I'll demonstrate an extremely simple method that does not use the cumbersome binomial expansion forumla and you may thank me for it, later. LOL.

This is how the binomial expansion is done mentally:

I'll demonstrate it in long form:

(a + b)^3 =?

1 x a^3 b^0 +......a^2b^1 (begin with the highest power for a and keep reducing that by 1 for each succeeding term of a and begin with b^0 and keep adding 1 for each successive term of b).

Now, what about the numerical co-efficient of the 2nd term a^2b^1?

.......a^2b^1 =?

Go to the previous term which is: 1 x a^3 b^0

Now, multiply the numerical coefficient of a which is 1 with the power of a which is 3.

So, 1 x 3 = 3.

Next, consider the succeeding term which is a^2b^1.

Take the power of b which happens to be 1 and divide the previous result 1 x 3 = 3 by 1.

So, 3/1 = 3.

This, then, is the numerical coefficient of the second term a^2b^1 which would be written as 3a^2b^1.

Now, multiply, as shown above, the numerical co-efficient of a which is 3 with the index of a which is 2 to get 3 x 2 = 6.

Divide this with the power of b in the succeeding term which is ......a^1b^2.

So, 6/2 = 3.

Thus, the numerical coefficient of the third term a^1b^2 is 3a^1b^2.

Finally, take the 4th term which is:....a^0b^3.

Now, the third term is: 3a^1b^2.

So, multiply the numerical coefficient of a which is 3 with the power of a which is 1 to get 3 x 1 = 3.

Divide 3 by the power of b in the 4th term which happens to be 3.

So, 3/3 = 1.

So, the 4th term can be written as: 1 x a^0b^3.

Now, add all the results together:

1 x a^3 b^0 + 3a^2b^1 + 3a^1b^2 + 1 x a^0b^3

Rewriting:

a^3 + 3a^2b + 3ab^2 + b^3.

(Note = n^0 = 1).

These steps can be worked out mentally in a matter of seconds.

(smiles)

“Legumes of the World Unite ”

Since: Sep 11

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#56211
Jul 22, 2013
 
JOEL THUMBS UP wrote:
Most Americans say that the plural of the word formula is formulas when actually it should be formulae. LOL.
According to Merriam-Webster, either formulas OR formulae is acceptable English

http://www.merriam-webster.com/dictionary/for...

Dont be so quick to expectorate without performing due diligence first

Since: May 13

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#56212
Jul 22, 2013
 
HUGH,

A-Level Dunce,

Learn Math from a nerd in math like me.

I can teach you many things in elementary and advanced math.

Ooooo, Hugh is in bed with his boyfriend.

I'm not getting into the shower with you, Hugh.

If I do, I'll keep my boxers on...maybe you'll get to see the silhouette of my beautiful pink dick through the wet fabric.

(wink wink wink)

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#56214
Jul 22, 2013
 
Good night. I have some studying to do for an hour or so before I relax. Thereafter, I may sit in the 24/7 Italian restaurant of the Taj Vivanta. Bye.

Since: Aug 11

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#56215
Jul 22, 2013
 
Frijoles wrote:
<quoted text>
The thing is, I think that in the intellectual environment that MUQ swims in, his missives ARE considered reasoned. I dont think he is used to being challenged, nor do I think he would survive very long out of his subculture.
In MUQ's defense, we have no shortage of anti-intellectuals here as well (think Tea Party, Christian Right, etc...). Only difference is the topic of conversation.

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