Question: 1
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure that the following requirements are met: Students must be ranked based on their average marks. If one or more students have the same average, incremental ranks must be given based on the order they are created. Ranks must be sequential without gaps in between. Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks) tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
Answer: C


Question: 2
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure that the following requirements are met: Students must be ranked based on their average marks. If one or more students have the same average, the same rank must be given to these students. Consecutive ranks must be skipped when the same rank is assigned. Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks) tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
Answer: A

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